Arithmetic question
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Arithmetic question
Hi
If you cannot add apples to oranges (or feet to pounds, etc), how come you can multiply them? I thought multiplication was repeated addition
I understand that this provides a new unit through dimensional analysis (ie foot-pounds), but how can this be explained conceptually?
If you cannot add apples to oranges (or feet to pounds, etc), how come you can multiply them? I thought multiplication was repeated addition
I understand that this provides a new unit through dimensional analysis (ie foot-pounds), but how can this be explained conceptually?
Re: Arithmetic question
Little Johnny went to the market. From Mr William, he bought 5 apples. From Mrs Donnel, he bought 7 eggs. And from Mr Patterson, he bought 3 oranges. How many fruit is there in little Johnny's basket?d-gun wrote:you cannot add apples to oranges
Re: Arithmetic question
that was tricky but you see we are adding FRUIT, not APPLES and ORANGES.
5 fruit + 3 fruit = 8 fruit.
5 apples + 3 oranges = ???? (appanges?) this does not compute
5 fruit + 3 fruit = 8 fruit.
5 apples + 3 oranges = ???? (appanges?) this does not compute
Re: Arithmetic question
if you have 6a where a is apple in means you have (a,a,a,a,a,a) you cannot resolve 6a+5o because the a and o represent non-numeric values. If you say wanted to get the combined weight of it you would then find out the weight of apples and oranges(assuming they all weigh the same) and then give a value to a and o. So it would be something like
a = 2
o = 1
which would give you 6(2)+5(1)
Apple and orange represent an abstract item until defined.
for feet/pounds or feet*pounds you would need to find how many feet or pounds. This isn't hard stuff. if you have say 1 square foot of something that weights one pound you can then resolve it.
I am unsure of what your conundrum is
a = 2
o = 1
which would give you 6(2)+5(1)
Apple and orange represent an abstract item until defined.
for feet/pounds or feet*pounds you would need to find how many feet or pounds. This isn't hard stuff. if you have say 1 square foot of something that weights one pound you can then resolve it.
I am unsure of what your conundrum is
Re: Arithmetic question
it is. the right things must be added together.I thought multiplication was repeated addition
if you spam 5 flash for 100 metal each you can not calculate
5 flash + 100 metal = something
but to calculate the total prize you can do "repeated addition"
100 metal +100 metal +100 metal +100 metal +100 metal = 500 metal
->
5 flash * 100 metal = total cost= 500 metal
Re: Arithmetic question
Multiply apples by oranges? o_Ohow come you can multiply them?
Re: Arithmetic question
Problem statement we have 5 flash, each costs 100 what is the total cost.knorke wrote:it is. the right things must be added together.I thought multiplication was repeated addition
if you spam 5 flash for 100 metal each you can not calculate
5 flash + 100 metal = something
but to calculate the total prize you can do "repeated addition"
100 metal +100 metal +100 metal +100 metal +100 metal = 500 metal
->
5 flash * 100 metal = total cost= 500 metal
Or cost = 100
x = cost
f(x) = 5(x)
f(100) = 500
lets play with apples and oranges.
Problem statement we have 5 flash, each costs 100 apples and 200 oranges. The apples and oranges weigh 50 pounds what is the total weight storage needed for the cost of a flash.
Or weight = 50
a = 100
o = 200
5(50(a+o))
does this help?
If you cannot define apples and oranges as some sort of quantitative unit you will not be able to use them. Apple and orange is abstract so you have to decide on what about the apples and oranges you are trying to evaluate.
Re: Arithmetic question
You do realize how units work right?d-gun wrote:Hi
If you cannot add apples to oranges (or feet to pounds, etc), how come you can multiply them? I thought multiplication was repeated addition
I understand that this provides a new unit through dimensional analysis (ie foot-pounds), but how can this be explained conceptually?
Notice "miles per hour" is your "oranges * (1/apples)".
no need to be mean about it - moderation
Re: Arithmetic question
I prefer the wording: a hundred metal per flash. Where "per" is represented by a slash.if you spam 5 flash for 100 metal each
''''5 flash x 100 metal / flash
' ' ' ' ' ' ' ' ' ' ' ' ' ' 'metal
= 5 flash x 100 -------
' ' ' ' ' ' ' ' ' ' ' ' ' ' 'flash
' ' ' ' ' ' ' ' ' ' ' ' ' ' 'metal
= 5
' ' ' ' ' ' ' ' ' ' ' ' ' ' '
= 5 x 100 x metal
= 500 metal
But the teacher never allows me to keep units in equations! ;_;
Re: Arithmetic question
Ok, lets use a real-world example:
I am loading 100-pound drums on a truck by rolling them up a ramp. The truck bed is 3 feet above the street and the ramp is 6 feet long. How much force must I exert on the drums as I go up the ramp?

3ft x 100lb = 300 ft-lb of work (drums end up with more energy)
6ft x ??? lb = 300 fl-lb? (where ??? = how many pounds of force must be exerted to give 300fl-lb of work)
the answer is 50 lb of force.
If you cannt add feet and pounds, how come you can multiply them?
I am loading 100-pound drums on a truck by rolling them up a ramp. The truck bed is 3 feet above the street and the ramp is 6 feet long. How much force must I exert on the drums as I go up the ramp?

3ft x 100lb = 300 ft-lb of work (drums end up with more energy)
6ft x ??? lb = 300 fl-lb? (where ??? = how many pounds of force must be exerted to give 300fl-lb of work)
the answer is 50 lb of force.
If you cannt add feet and pounds, how come you can multiply them?
Last edited by d-gun on 24 Sep 2010, 17:03, edited 1 time in total.
Re: Arithmetic question
Syst├¿me international d'unit├®s, motherf*****, do you speak it?
Re: Arithmetic question
Err, feet and pound are archaic units. They don't give nice joules when multiplied.3ft x 100lb = 300 joules of work
The real formula would be:
height x weight x gravity = energy
3 feet x 100 pound * 9.81m/s┬▓ =
0.914 meters * 45.36 kilograms * 9.81m/s┬▓ = 407 joules
Re: Arithmetic question
x+y=x+yd-gun wrote:If you cannt add feet and pounds, how come you can multiply them?
x*y=xy
Re: Arithmetic question
right, it should have been ft-lb not joules, thanks.zwzsg wrote:Err, feet and pound are archaic units. They don't give nice joules when multiplied.3ft x 100lb = 300 joules of work
The real formula would be:
height x weight x gravity = energy
3 feet x 100 pound * 9.81m/s┬▓ =
0.914 meters * 45.36 kilograms * 9.81m/s┬▓ = 407 joules
The 100-lb drums end up 3 ft higher so they end up with 3ft * 300lb = 300 ft lb more energy
http://en.wikipedia.org/wiki/Foot-pound_(energy)
Re: Arithmetic question
at this point, thread failed.I am loading 100-pound drums
also in your barrel example, the length of the ramp does not matter, if there is no friction etc.
only heighth.
its all in the gravity
ie
potential energy = height * mass* g
g= 9,81m/s┬▓ (gravition)
edit
so its already been said.
well, how many red comet games did you play in the meantime!
Re: Arithmetic question
??? nobody cares about your silly french units of measurements. at my supermarket food is measured in lb.knorke wrote:at this point, thread failed.
the length of the ramp DOES matter a lot. it is an inclined plane designed to reduce the necessary force required to do a certain amount of work by increaseing the distance through which the force acts.
try unscrewing a bolt with your fingers, then get a wrench and try. levers, block-and-tackle, and compound pulleys work on the same principle.
anyway, you arent answering the question
addition: 1ft + 1lb = ...does not make sense...(there is no real-world thing for this to be a measure of, for example force or torque)
repeated addition: 1ft * 1lb = 1 pound-foot (a work)
i still dont get it...
Last edited by d-gun on 24 Sep 2010, 17:52, edited 1 time in total.
Re: Arithmetic question
d-gun wrote:??? nobody cares about your silly french units of measurements. at my supermarket food is measured in lb.
Re: Arithmetic question
at my supermarket yo momma always has already eaten all the food when i get there
but yes i didnt read the question correctly. i thought you were messing up required force and work or something, sorry.
The "drums end up with more energy" confused me but you meant something else.
One joule is defined as the amount of work done by a force of one newton moving an object through a distance of one metre
So I think it is just a defined this way.
Actually there are only 7 base units:
length, mass, electric current, temperature, strength of light, time.
Everything else is defined by them, even the "simple" ones we are so used to, ie speed.
Definations do not need to make "sense", there are just defined that way.
but yes i didnt read the question correctly. i thought you were messing up required force and work or something, sorry.
The "drums end up with more energy" confused me but you meant something else.
http://en.wikipedia.org/wiki/Joulerepeated addition: 1ft * 1lb = 1 pound-foot (a force)
i still dont get it...
One joule is defined as the amount of work done by a force of one newton moving an object through a distance of one metre
So I think it is just a defined this way.
Actually there are only 7 base units:
length, mass, electric current, temperature, strength of light, time.
Everything else is defined by them, even the "simple" ones we are so used to, ie speed.
Definations do not need to make "sense", there are just defined that way.
Re: Arithmetic question
I think he wanted to calculate the force needed to push a 100-lb drum upward a 30┬░ ramp. But instead he described the ramp as being 6 feet long and ending 3 feet above ground. Then he calculated the potential energy of a drum atop this particular kind of 30┬░ ramp, and equated it to the work needed to push the drum along the ramp, and got the force from there.knorke wrote:the length of the ramp does not matter
Because on earth surface gravitation is nearly constant, any mass units (such as pound) double as a force unit. It's not very rigourous, but people often talk about kilogram-force, or in this case, pound-force. So beside the confusion between imperial and SI energy units that he just edited out, it's not thaaaat wrong.
Nein! A work!d-gun wrote:1 pound-foot (a force)
Take care when using the words: work, force, energy, weight, mass. They all have their own meaning. Ok, work and energy are the same dimension, and the weight is a kind of force. But a force multiplied by a length is a work.
Last edited by zwzsg on 24 Sep 2010, 17:57, edited 2 times in total.
